x^2-0.65x+0.025=0

Solution for x^2-0.65x+0.025=0 equation:

x^2-0.65x+0.025=0

a = 1; b = -0.65; c = +0.025;
Δ = b2-4ac
Δ = -0.652-4·1·0.025
Δ = 0.3225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.65)-\sqrt{0.3225}}{2*1}=\frac{0.65-\sqrt{0.3225}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.65)+\sqrt{0.3225}}{2*1}=\frac{0.65+\sqrt{0.3225}}{2}
$